[Numpy-discussion] dimension independent copy of corner of array

[Neal Becker]

I want to copy an array to the corner of a new array. What is a dimension
independent way to say:

newarr[:i0,:i1,...] = oldarray

where (i0,i1...) is oldarray.shape?

[Robert Kern]

newarr[tuple(slice(0, i) for i in oldarray.shape)] = oldarray

Post by Neal Becker
I want to copy an array to the corner of a new array. What is a dimension
newarr[:i0,:i1,...] = oldarray
where (i0,i1...) is oldarray.shape?
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[Neal Becker]

Post by Robert Kern
newarr[tuple(slice(0, i) for i in oldarray.shape)] = oldarray

Post by Neal Becker
I want to copy an array to the corner of a new array. What is a
newarr[:i0,:i1,...] = oldarray
where (i0,i1...) is oldarray.shape?

Thanks. I'm making my own class that represents a resizeable array that
works by preserving the lower corner of the old data, because I believe that
ndarray arr.resize does not actually work this way. I'm only interested in
resizing to a larger size. Is this correct?